TM 5-6630-215-12Table 2-2. Sample Sizes for Low ConcentrationsMeasuring - Water sampleMultiply indicatorDivide ResultTubesize(and buffer, if any) used by:By115 ml230 ml45 ml460 ml123412343(1) Standard additions is performed by adding a small amount ofa standard solution to a previously analyzed sample and then repeatingthe analysis using the same reagent,instrument and technique.Theamount of increase in the test result should exactly equal the amountof standard added.(2) For example, if a 25-ml water sample is analyzed for ironand is found to contain 1.0 mg/l, the result can be checked by adding0.10 ml of a 50.0 mg/l iron standard solution to another 25-ml portionof the water sample and repeating the analysis.The result of theanalysis on the second sample should be 1.2 mg/l iron since thestandard added has a value of 0.2 mg/l; i.e.,0.1 mlX 50 mg/l = 0.2 mg/l25 mlIf 0.2 mg/l is recovered from the 0.2 mg/l addition, the analyst canconclude that the first answer was correct and that the reagents,instruments and method used are all working properly.Table 2-3. Dilutions for High ConcentrationsWater sample(use pipet)50.0 ml25.0 ml10.0 ml5.0 mlDemineralized water usedto bring volume to approximately50 ml (use graduated cylinder)0 ml25 ml40 ml45 mlMultiplicationfactor12510(3) Should the second analysis not give the correct amount ofincrease in the iron content, it must be concluded that the firstanswer may also be incorrect.The analyst must then determine why thetechnique did not work.By using a logical troubleshooting approach,the source of the problems can be determined whether the fault lies inthe reagent, the instrument and apparatus, the test procedure or aninterfering substance present in the test sample.2-9
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